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  • Verbal - 166
  • Quans - 170
  • Total - 336
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GRE Practice Test

GRE Practice: Numeric Entry GRE Practice Test 4

Good you are taking our practice tests. But please make sure you complete all the practice problems from Official GRE Guide. Official GRE Guide is from the test makers(Yes You read it right they conduct the GRE exam worldwide.) ETS.:- The Official Guide to the GRE General Test, Third Edition
Powered by GreGuide Version 2.2.1 Copyrights 2007,

Question: 1

Pat has a weight problem. He exercises for three months and reduces his weight by 40%. He meets with an accident and fractures his leg, thereby increasing his weight by 50% in two months. What was his weight loss percent at the end of the five-month period?

Correct Answer: 10%


Let his original weight be 100 kg.
Weight after the first three months = 100 kg - 40% of 100 kg
= 100 - 40 = 60 kg
Weight after the next two months = 60 + 50% of 60 kg
= 60 + 30 = 90 kg
Loss % = (Initial weight - final weight)/initial weight*100
= (100-90)/100*100
= 10%
He lost 10% of his weight in five months.

Question: 2

The house of Laura is 60 meters west and 70 meters north of a crossing. The house of Ann is 10 meters west and 50 meters south of the same crossing. What is the distance between their houses in meters?

Correct Answer: 130 meters


The crossing can be considered as an origin and the four directions can be taken as the four axes.
The co-ordinates of the houses of Laura and Ann will be (-60, 70) and (-10, -50).
Distance between the points given = sqrt[(-10+60)^2+(-50-70)^2]
= sqrt[50^2+(-120)^2] = sqrt(2500+14400)
= sqrt(16900) = 130
The distance is 130 meters.
[sqrt(2) = square root of 2,[2^2 = 2*2]

Question: 3

What is the difference between the mean of the first 5 odd numbers and the mean of the first 5 even numbers?

Correct Answer: 1


The mean of the first 5 odd numbers = (1+3+5+7+9)/5
= 25/5 = 5
The mean of the first 5 even numbers = (2+4+6+8+10)/5
= 30/5 = 6
Difference = 6-5 = 1

Question: 4

There are 10 flags of different colours. Tim has to prepare 2 different arrangements, each using 4 flags of different colours. How many different arrangements can he possibly make if the flags of one set cannot be used in the other?

Correct Answer: 1814400


Tim can pick the first four flags from the ten flags in P(10,4) ways.
He will then be left with 6 flags out of which he can pick the next four in P(6,4) ways.
Total number of arrangements = P(10,4)*P(6,4)
= 10!/(10-4)! * 6!/(6-4)!
= 10!/6! * 6!/2!
= 10!/2!
= 1814400

Question: 5

A variable is such that it satisfies the quadratic equation 9x^2-63x-162 = 0. Find the natural number.
[x^2 = x*x]

Correct Answer: 9


9x^2-63x-162 = 0
x^2 -7x -18 = 0
x^2 - 9x + 2x -18 = 0
x(x - 9) + 2(x - 9) = 0
(x-9)(x+2) = 0
x = 9, -2
Since x is a natural number, it is equal to 9

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