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GRE Practice Test

GRE Practice: Numeric Entry GRE Practice Test 5

Good you are taking our practice tests. But please make sure you complete all the practice problems from Official GRE Guide. Official GRE Guide is from the test makers(Yes You read it right they conduct the GRE exam worldwide.) ETS.:- The Official Guide to the GRE General Test, Third Edition Powered by GreGuide Version 2.2.1 Copyrights 2007, GreGuide.com

Question: 1

The least common multiple of two numbers is 44 and the highest common factor of the numbers is 264. How many such pairs of numbers exist?

Correct Answer: 2

Explanation:

Product of two numbers = LCM of the numbers/HCF of the numbers
= 264/44
= 6
Pairs of numbers whose product is 6 are (1,6) and (2,3).
Two such pairs of numbers exist.

Question: 2

The average of the sacks lifted by each of 70 workers in a day is 30. Ten workers are sick on a paricular day and others have to share their work. On an average, how many additional sacks will be lifted by each worker on that day?

Correct Answer: 5

Explanation:

Total number of sacks lifted by each worker = Total workers * Average of sacks lifed
= 70 * 30
= 2100
Since 10 workers fall ill, there are 70-10=60 left to lift 2100 sacks.
Average sacks lifted by each worker = 2100/60
= 35
Each worker has to lift 35-30=5 additional sacks on an average.

Question: 3

In a game show, each participant has to pay $10 as entry fee. The game is played in sets of 7. There are first, second and third prizes of $20, $15 and $10 respectively, two consolation prizes of $5 each and two participants do not get any prize at all. The game is played 17 times, out of which the results were inconclusive on 3 occasions and hence no prizes were given. How much did the organizers profit in dollars?

Correct Answer: 420

Explanation:

Money earned by the organizers when the game was conducted 17 times = 17*7*10
= $1190

Money given as prizes in (17-3) = 14 successful games = 14 *($20 + $15 + $10 + $5*2)
= 14*$55 = $770

Profit of organizers = 1190-770
= $420
The organizers gained $420

Question: 4

A man weighs 70 kgs at the age of 65. He steadily loses weight in the next few years at the rate of 5%. Approximately how many kgs (rounded to the nearest whole number) does he weigh when he is 67 years old?

Correct Answer: 63

Explanation:

This problem can be compared to a compound interest problem where the rate of interest is negative.
Here the original weight is 70 kgs.
The time to be considered is (67-65) = 2 years
Weight at end of 2 years = P(1-r/100)^t, where P, r and t are the principle, rate and time.
= 70(1-5/100)^2
= 70(19/20)^2
= 70*19*19/(20*20)
= 63.175 kg
= 63 kgs

[r^t = r*r*r*...t times]

Question: 5

There are three teams A, B and C containing 5, 4 and 5 equally skilled members respectively. If teams A, B and C can complete a set of tasks in 2, 3 and 3 days respectively, then how many days will it take a fourth team to complete the work when it comprises of three members, one from each of the three teams?

Correct Answer: 4

Explanation:

Time taken by one member of team A to complete the work = 5*2 days
Work done by one member of team B in one day = 1/(5*2)
Similarly, work done by one member of team B in one day = 1/(4*3)
Work done by one member of team C in one day = 1/(5*3)
Work done by the three members of the fourth team in one day = 1/(5*2) + 1/(4*3) + 1/(5*3)
= (6+5+4)/(3*4*5) = 15/(3*4*5)
= 1/4
Time taken by the fourth team to complete the task = 4 days

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